I'm a professional game developer from Wakefield, England, working as a senior programmer for Rebellion North.
I'm a married father of five and I a also sometimes do Retroburn stuff.
Martin 'Bytrix' Caine
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Monday, May 31st 2010 / Web

Project Euler - Problem 6

It took less than a minute to complete puzzle number 6 from Project Euler:

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

This simply required working up from 1 to 100 and keeping a sum and a sum of their squares. Finally, I squared the sum and substracted the summed squares:


<?
/******************************************************************
*  ProjectEuler.net  *  Problem 6  *  2010-05-31  *  Martin Caine *
******************************************************************/

$totalSum 0;
$totalSquares 0;

for( 
$i=1$i<101$i++ )
{
    
$totalSum += $i;
    
$totalSquares += ($i*$i);
}

$totalSum *= $totalSum;

echo 
$totalSum-$totalSquares;

?>



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