I'm a professional game developer from Wakefield, England, working for TickTock Games.
I'm a married father of five and I am also the director and lead programmer of Retroburn Ltd.
Martin 'Bytrix' Caine
Father. C++ Games Programmer. Cyclist. Guitarist.
Monday, May 31st 2010 / Web

# Project Euler - Problem 6

It took less than a minute to complete puzzle number 6 from Project Euler:

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

This simply required working up from 1 to 100 and keeping a sum and a sum of their squares. Finally, I squared the sum and substracted the summed squares:

``` <?/*******************************************************************  ProjectEuler.net  *  Problem 6  *  2010-05-31  *  Martin Caine *******************************************************************/\$totalSum = 0;\$totalSquares = 0;for( \$i=1; \$i<101; \$i++ ){    \$totalSum += \$i;    \$totalSquares += (\$i*\$i);}\$totalSum *= \$totalSum;echo \$totalSum-\$totalSquares;?> ```     